2x-3=2(x+4)2

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Solution for 2x-3=2(x+4)2 equation: 



2x-3=2(x+4)2

We move all terms to the left:

2x-3-(2(x+4)2)=0



We calculate terms in parentheses: -(2(x+4)2), so:

2(x+4)2

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

2x-4x-16-3=0

We add all the numbers together, and all the variables

-2x-19=0

We move all terms containing x to the left, all other terms to the right

-2x=19

x=19/-2

x=-9+1/2

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