2x-3+12x=4(5x-3)+6

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Solution for 2x-3+12x=4(5x-3)+6 equation: 



2x-3+12x=4(5x-3)+6

We move all terms to the left:

2x-3+12x-(4(5x-3)+6)=0

We add all the numbers together, and all the variables

14x-(4(5x-3)+6)-3=0



We calculate terms in parentheses: -(4(5x-3)+6), so:

4(5x-3)+6

We multiply parentheses

20x-12+6

We add all the numbers together, and all the variables

20x-6

Back to the equation:

-(20x-6)



We get rid of parentheses

14x-20x+6-3=0

We add all the numbers together, and all the variables

-6x+3=0

We move all terms containing x to the left, all other terms to the right

-6x=-3

x=-3/-6

x=1/2

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