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5(2x-3)-5x=1-6(3x-5)
We move all terms to the left:
5(2x-3)-5x-(1-6(3x-5))=0
We add all the numbers together, and all the variables
-5x+5(2x-3)-(1-6(3x-5))=0
We multiply parentheses
-5x+10x-(1-6(3x-5))-15=0
We calculate terms in parentheses: -(1-6(3x-5)), so:We add all the numbers together, and all the variables
1-6(3x-5)
determiningTheFunctionDomain -6(3x-5)+1
We multiply parentheses
-18x+30+1
We add all the numbers together, and all the variables
-18x+31
Back to the equation:
-(-18x+31)
5x-(-18x+31)-15=0
We get rid of parentheses
5x+18x-31-15=0
We add all the numbers together, and all the variables
23x-46=0
We move all terms containing x to the left, all other terms to the right
23x=46
x=46/23
x=2
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