2x-3(x-4)=6(2x+1)

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Solution for 2x-3(x-4)=6(2x+1) equation: 



2x-3(x-4)=6(2x+1)

We move all terms to the left:

2x-3(x-4)-(6(2x+1))=0

We multiply parentheses

2x-3x-(6(2x+1))+12=0



We calculate terms in parentheses: -(6(2x+1)), so:

6(2x+1)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We add all the numbers together, and all the variables

-1x-(12x+6)+12=0

We get rid of parentheses

-1x-12x-6+12=0

We add all the numbers together, and all the variables

-13x+6=0

We move all terms containing x to the left, all other terms to the right

-13x=-6

x=-6/-13

x=6/13

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