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16/(x+3)=2
We move all terms to the left:
16/(x+3)-(2)=0
Domain of the equation: (x+3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
-2*(x+3)+16=0
We multiply parentheses
-2x-6+16=0
We add all the numbers together, and all the variables
-2x+10=0
We move all terms containing x to the left, all other terms to the right
-2x=-10
x=-10/-2
x=+5
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