2x-3(x+1)=-(6x-7)+x

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Solution for 2x-3(x+1)=-(6x-7)+x equation: 



2x-3(x+1)=-(6x-7)+x

We move all terms to the left:

2x-3(x+1)-(-(6x-7)+x)=0

We multiply parentheses

2x-3x-(-(6x-7)+x)-3=0



We calculate terms in parentheses: -(-(6x-7)+x), so:

-(6x-7)+x

We add all the numbers together, and all the variables

x-(6x-7)

We get rid of parentheses

x-6x+7

We add all the numbers together, and all the variables

-5x+7

Back to the equation:

-(-5x+7)



We add all the numbers together, and all the variables

-1x-(-5x+7)-3=0

We get rid of parentheses

-1x+5x-7-3=0

We add all the numbers together, and all the variables

4x-10=0

We move all terms containing x to the left, all other terms to the right

4x=10

x=10/4

x=2+1/2

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