-3x-3(3-4x)=3(x-4)-9

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Solution for -3x-3(3-4x)=3(x-4)-9 equation:



-3x-3(3-4x)=3(x-4)-9
We move all terms to the left:
-3x-3(3-4x)-(3(x-4)-9)=0
We add all the numbers together, and all the variables
-3x-3(-4x+3)-(3(x-4)-9)=0
We multiply parentheses
-3x+12x-(3(x-4)-9)-9=0
We calculate terms in parentheses: -(3(x-4)-9), so:
3(x-4)-9
We multiply parentheses
3x-12-9
We add all the numbers together, and all the variables
3x-21
Back to the equation:
-(3x-21)
We add all the numbers together, and all the variables
9x-(3x-21)-9=0
We get rid of parentheses
9x-3x+21-9=0
We add all the numbers together, and all the variables
6x+12=0
We move all terms containing x to the left, all other terms to the right
6x=-12
x=-12/6
x=-2

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