2x-2+4x=12-(2x+6)

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Solution for 2x-2+4x=12-(2x+6) equation: 



2x-2+4x=12-(2x+6)

We move all terms to the left:

2x-2+4x-(12-(2x+6))=0

We add all the numbers together, and all the variables

6x-(12-(2x+6))-2=0



We calculate terms in parentheses: -(12-(2x+6)), so:

12-(2x+6)

determiningTheFunctionDomain
-(2x+6)+12

We get rid of parentheses

-2x-6+12

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We get rid of parentheses

6x+2x-6-2=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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