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a+5(2a+1)+3=11a-2
We move all terms to the left:
a+5(2a+1)+3-(11a-2)=0
We multiply parentheses
a+10a-(11a-2)+5+3=0
We get rid of parentheses
a+10a-11a+2+5+3=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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