2x-2(3x-2)=6x+10

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Solution for 2x-2(3x-2)=6x+10 equation: 



2x-2(3x-2)=6x+10

We move all terms to the left:

2x-2(3x-2)-(6x+10)=0

We multiply parentheses

2x-6x-(6x+10)+4=0

We get rid of parentheses

2x-6x-6x-10+4=0

We add all the numbers together, and all the variables

-10x-6=0

We move all terms containing x to the left, all other terms to the right

-10x=6

x=6/-10

x=-3/5

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