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(x-9)(x)=400
We move all terms to the left:
(x-9)(x)-(400)=0
We multiply parentheses
x^2-9x-400=0
a = 1; b = -9; c = -400;
Δ = b2-4ac
Δ = -92-4·1·(-400)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-41}{2*1}=\frac{-32}{2} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+41}{2*1}=\frac{50}{2} =25 $
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