2x-19=4(2x-2)-5

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Solution for 2x-19=4(2x-2)-5 equation: 



2x-19=4(2x-2)-5

We move all terms to the left:

2x-19-(4(2x-2)-5)=0



We calculate terms in parentheses: -(4(2x-2)-5), so:

4(2x-2)-5

We multiply parentheses

8x-8-5

We add all the numbers together, and all the variables

8x-13

Back to the equation:

-(8x-13)



We get rid of parentheses

2x-8x+13-19=0

We add all the numbers together, and all the variables

-6x-6=0

We move all terms containing x to the left, all other terms to the right

-6x=6

x=6/-6

x=-1

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