41=2(5x-4)+9

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Solution for 41=2(5x-4)+9 equation: 



41=2(5x-4)+9

We move all terms to the left:

41-(2(5x-4)+9)=0



We calculate terms in parentheses: -(2(5x-4)+9), so:

2(5x-4)+9

We multiply parentheses

10x-8+9

We add all the numbers together, and all the variables

10x+1

Back to the equation:

-(10x+1)



We get rid of parentheses

-10x-1+41=0

We add all the numbers together, and all the variables

-10x+40=0

We move all terms containing x to the left, all other terms to the right

-10x=-40

x=-40/-10

x=+4

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