2x-(x-(3x-(8x+9)))=6x-1

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Solution for 2x-(x-(3x-(8x+9)))=6x-1 equation: 



2x-(x-(3x-(8x+9)))=6x-1

We move all terms to the left:

2x-(x-(3x-(8x+9)))-(6x-1)=0

We get rid of parentheses

2x-(x-(3x-(8x+9)))-6x+1=0



We calculate terms in parentheses: -(x-(3x-(8x+9))), so:

x-(3x-(8x+9))



We calculate terms in parentheses: -(3x-(8x+9)), so:

3x-(8x+9)

We get rid of parentheses

3x-8x-9

We add all the numbers together, and all the variables

-5x-9

Back to the equation:

-(-5x-9)



We get rid of parentheses

x+5x+9

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We add all the numbers together, and all the variables

-4x-(6x+9)+1=0

We get rid of parentheses

-4x-6x-9+1=0

We add all the numbers together, and all the variables

-10x-8=0

We move all terms containing x to the left, all other terms to the right

-10x=8

x=8/-10

x=-4/5

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