0.25(2x+1.2)=3(0.7x+3)-5.5

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Solution for 0.25(2x+1.2)=3(0.7x+3)-5.5 equation: 



0.25(2x+1.2)=3(0.7x+3)-5.5

We move all terms to the left:

0.25(2x+1.2)-(3(0.7x+3)-5.5)=0

We multiply parentheses

0.5x-(3(0.7x+3)-5.5)+0.3=0



We calculate terms in parentheses: -(3(0.7x+3)-5.5), so:

3(0.7x+3)-5.5

We multiply parentheses

0x+9-5.5

We add all the numbers together, and all the variables

x+3.5

Back to the equation:

-(x+3.5)



We get rid of parentheses

0.5x-x-3.5+0.3=0

We add all the numbers together, and all the variables

-0.5x-3.2=0

We move all terms containing x to the left, all other terms to the right

-0.5x=3.2

x=3.2/-0.5

x=-6+0.2/0.5

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