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2x-(5-x)+(3x+9)=16
We move all terms to the left:
2x-(5-x)+(3x+9)-(16)=0
We add all the numbers together, and all the variables
2x-(-1x+5)+(3x+9)-16=0
We get rid of parentheses
2x+1x+3x-5+9-16=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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