2x-(5-x)=16-(3x+9)

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Solution for 2x-(5-x)=16-(3x+9) equation: 



2x-(5-x)=16-(3x+9)

We move all terms to the left:

2x-(5-x)-(16-(3x+9))=0

We add all the numbers together, and all the variables

2x-(-1x+5)-(16-(3x+9))=0

We get rid of parentheses

2x+1x-(16-(3x+9))-5=0



We calculate terms in parentheses: -(16-(3x+9)), so:

16-(3x+9)

determiningTheFunctionDomain
-(3x+9)+16

We get rid of parentheses

-3x-9+16

We add all the numbers together, and all the variables

-3x+7

Back to the equation:

-(-3x+7)



We add all the numbers together, and all the variables

3x-(-3x+7)-5=0

We get rid of parentheses

3x+3x-7-5=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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