2x-(3x+19)=9(x-1)

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Solution for 2x-(3x+19)=9(x-1) equation: 



2x-(3x+19)=9(x-1)

We move all terms to the left:

2x-(3x+19)-(9(x-1))=0

We get rid of parentheses

2x-3x-(9(x-1))-19=0



We calculate terms in parentheses: -(9(x-1)), so:

9(x-1)

We multiply parentheses

9x-9

Back to the equation:

-(9x-9)



We add all the numbers together, and all the variables

-1x-(9x-9)-19=0

We get rid of parentheses

-1x-9x+9-19=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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