4(3+y)=2(y+1)

Solution for 4(3+y)=2(y+1) equation:

4(3+y)=2(y+1)

We move all terms to the left:

4(3+y)-(2(y+1))=0

We add all the numbers together, and all the variables

4(y+3)-(2(y+1))=0

We multiply parentheses

4y-(2(y+1))+12=0


We calculate terms in parentheses: -(2(y+1)), so:

2(y+1)

We multiply parentheses

2y+2

Back to the equation:

-(2y+2)


We get rid of parentheses

4y-2y-2+12=0

We add all the numbers together, and all the variables

2y+10=0

We move all terms containing y to the left, all other terms to the right

2y=-10

y=-10/2

y=-5