2x+x+1/2x-2=180

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Solution for 2x+x+1/2x-2=180 equation:



2x+x+1/2x-2=180
We move all terms to the left:
2x+x+1/2x-2-(180)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
3x+1/2x-182=0
We multiply all the terms by the denominator
3x*2x-182*2x+1=0
Wy multiply elements
6x^2-364x+1=0
a = 6; b = -364; c = +1;
Δ = b2-4ac
Δ = -3642-4·6·1
Δ = 132472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{132472}=\sqrt{4*33118}=\sqrt{4}*\sqrt{33118}=2\sqrt{33118}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-364)-2\sqrt{33118}}{2*6}=\frac{364-2\sqrt{33118}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-364)+2\sqrt{33118}}{2*6}=\frac{364+2\sqrt{33118}}{12} $

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