6(m+2)-2m=28

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Solution for 6(m+2)-2m=28 equation: 



6(m+2)-2m=28

We move all terms to the left:

6(m+2)-2m-(28)=0

We add all the numbers together, and all the variables

-2m+6(m+2)-28=0

We multiply parentheses

-2m+6m+12-28=0

We add all the numbers together, and all the variables

4m-16=0

We move all terms containing m to the left, all other terms to the right

4m=16

m=16/4

m=4

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