2x+7x2-6x=3x2=

Solution for 2x+7x2-6x=3x2= equation:

2x+7x^2-6x=3x^2=

We move all terms to the left:

2x+7x^2-6x-(3x^2)=0

determiningTheFunctionDomain
7x^2-3x^2+2x-6x=0

We add all the numbers together, and all the variables

4x^2-4x=0

a = 4; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·4·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*4}=\frac{8}{8}
=1
$