2x+6/3x-3x+1/5x=7/15

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Solution for 2x+6/3x-3x+1/5x=7/15 equation: 



2x+6/3x-3x+1/5x=7/15

We move all terms to the left:

2x+6/3x-3x+1/5x-(7/15)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

2x+6/3x-3x+1/5x-(+7/15)=0

We add all the numbers together, and all the variables

-1x+6/3x+1/5x-(+7/15)=0

We get rid of parentheses

-1x+6/3x+1/5x-7/15=0

We calculate fractions


(-525x^2)/225x^2-1x+450x/225x^2+45x/225x^2=0

We multiply all the terms by the denominator


(-525x^2)-1x*225x^2+450x+45x=0

We add all the numbers together, and all the variables

(-525x^2)+495x-1x*225x^2=0

Wy multiply elements

(-525x^2)-225x^3+495x=0

We get rid of parentheses

-525x^2-225x^3+495x=0

We do not support expression: x^3

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