(4x+35)(x+60)=0

Solution for (4x+35)(x+60)=0 equation:

(4x+35)(x+60)=0

We multiply parentheses ..

(+4x^2+240x+35x+2100)=0

We get rid of parentheses

4x^2+240x+35x+2100=0

We add all the numbers together, and all the variables

4x^2+275x+2100=0

a = 4; b = 275; c = +2100;
Δ = b2-4ac
Δ = 2752-4·4·2100
Δ = 42025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{42025}=205$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(275)-205}{2*4}=\frac{-480}{8}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(275)+205}{2*4}=\frac{-70}{8}
=-8+3/4
$