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2x+5-x=10-(2x+5)
We move all terms to the left:
2x+5-x-(10-(2x+5))=0
We add all the numbers together, and all the variables
x-(10-(2x+5))+5=0
We calculate terms in parentheses: -(10-(2x+5)), so:We get rid of parentheses
10-(2x+5)
determiningTheFunctionDomain -(2x+5)+10
We get rid of parentheses
-2x-5+10
We add all the numbers together, and all the variables
-2x+5
Back to the equation:
-(-2x+5)
x+2x-5+5=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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