1/2k-7=1/3(k-12)

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Solution for 1/2k-7=1/3(k-12) equation: 



1/2k-7=1/3(k-12)

We move all terms to the left:

1/2k-7-(1/3(k-12))=0



Domain of the equation: 2k!=0

k!=0/2

k!=0

k∈R





Domain of the equation: 3(k-12))!=0

k∈R



We calculate fractions


(3kk/(6k^2k+(-(1*2k)/(6k^2k-7=0

We can not solve this equation

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