2x+4x=18+2(5x-4)=12

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Solution for 2x+4x=18+2(5x-4)=12 equation: 



2x+4x=18+2(5x-4)=12

We move all terms to the left:

2x+4x-(18+2(5x-4))=0

We add all the numbers together, and all the variables

6x-(18+2(5x-4))=0



We calculate terms in parentheses: -(18+2(5x-4)), so:

18+2(5x-4)

determiningTheFunctionDomain
2(5x-4)+18

We multiply parentheses

10x-8+18

We add all the numbers together, and all the variables

10x+10

Back to the equation:

-(10x+10)



We get rid of parentheses

6x-10x-10=0

We add all the numbers together, and all the variables

-4x-10=0

We move all terms containing x to the left, all other terms to the right

-4x=10

x=10/-4

x=-2+1/2

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