9-(6x+1)=2(x-4)+27

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Solution for 9-(6x+1)=2(x-4)+27 equation: 



9-(6x+1)=2(x-4)+27

We move all terms to the left:

9-(6x+1)-(2(x-4)+27)=0

We get rid of parentheses

-6x-(2(x-4)+27)-1+9=0



We calculate terms in parentheses: -(2(x-4)+27), so:

2(x-4)+27

We multiply parentheses

2x-8+27

We add all the numbers together, and all the variables

2x+19

Back to the equation:

-(2x+19)



We add all the numbers together, and all the variables

-6x-(2x+19)+8=0

We get rid of parentheses

-6x-2x-19+8=0

We add all the numbers together, and all the variables

-8x-11=0

We move all terms containing x to the left, all other terms to the right

-8x=11

x=11/-8

x=-1+3/8

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