If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x+4-3/3x=1/3(x+5)
We move all terms to the left:
2x+4-3/3x-(1/3(x+5))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3(x+5))!=0We calculate fractions
x∈R
2x+(-9xx/(9x^2x+(-(1*3x)/(9x^2x+4=0
We can not solve this equation
| -(a-1)/4=-9 | | 7x-2+3x=180 | | 50x^2-x-950=0 | | (b-9)/2=-6 | | 3(4x+1)=2(3x+1) | | x³=1,125.10²³ | | x²=1,125.10²³ | | 83=270-u | | 9x+-7=50 | | (a+3)⁄7=3 | | -9x-13=-39 | | 2x-13=-6 | | 16-4n|=10 | | Y=7-15x | | 3x-8+10=20 | | 7x=+1=4x=-3 | | 7x=+14x=-3 | | 3(p+12)=10(p-9) | | x+3(1-x)-4=-4(x-1)-(2x-95) | | –6f=–5f+6 | | 16x-2=3x+7 | | 4j+2(j+1.5)*6=16 | | (7r+6)+(8r-8)=90 | | x/60=50/70 | | |9-7x/5|=19 | | 4(0)=6x+20 | | R^2=3a | | h(-1)=2 | | 22,1-t=5 | | Y/x=63 | | 9^x+1+8.3^x-1=0 | | X×(x-45)=0 |