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3(4x+1)=2(3x+1)
We move all terms to the left:
3(4x+1)-(2(3x+1))=0
We multiply parentheses
12x-(2(3x+1))+3=0
We calculate terms in parentheses: -(2(3x+1)), so:We get rid of parentheses
2(3x+1)
We multiply parentheses
6x+2
Back to the equation:
-(6x+2)
12x-6x-2+3=0
We add all the numbers together, and all the variables
6x+1=0
We move all terms containing x to the left, all other terms to the right
6x=-1
x=-1/6
x=-1/6
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