2x+4(x-3)+2-(x-4)=x+6

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Solution for 2x+4(x-3)+2-(x-4)=x+6 equation:



2x+4(x-3)+2-(x-4)=x+6
We move all terms to the left:
2x+4(x-3)+2-(x-4)-(x+6)=0
We multiply parentheses
2x+4x-(x-4)-(x+6)-12+2=0
We get rid of parentheses
2x+4x-x-x+4-6-12+2=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3

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