3(x+2)+x-5=7(x+1)-6

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Solution for 3(x+2)+x-5=7(x+1)-6 equation: 



3(x+2)+x-5=7(x+1)-6

We move all terms to the left:

3(x+2)+x-5-(7(x+1)-6)=0

We add all the numbers together, and all the variables

x+3(x+2)-(7(x+1)-6)-5=0

We multiply parentheses

x+3x-(7(x+1)-6)+6-5=0



We calculate terms in parentheses: -(7(x+1)-6), so:

7(x+1)-6

We multiply parentheses

7x+7-6

We add all the numbers together, and all the variables

7x+1

Back to the equation:

-(7x+1)



We add all the numbers together, and all the variables

4x-(7x+1)+1=0

We get rid of parentheses

4x-7x-1+1=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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