2x+3x+8=8(8-x)

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Solution for 2x+3x+8=8(8-x) equation: 



2x+3x+8=8(8-x)

We move all terms to the left:

2x+3x+8-(8(8-x))=0

We add all the numbers together, and all the variables

2x+3x-(8(-1x+8))+8=0

We add all the numbers together, and all the variables

5x-(8(-1x+8))+8=0



We calculate terms in parentheses: -(8(-1x+8)), so:

8(-1x+8)

We multiply parentheses

-8x+64

Back to the equation:

-(-8x+64)



We get rid of parentheses

5x+8x-64+8=0

We add all the numbers together, and all the variables

13x-56=0

We move all terms containing x to the left, all other terms to the right

13x=56

x=56/13

x=4+4/13

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