2(u+2)-u=3(u-+)+9

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Solution for 2(u+2)-u=3(u-+)+9 equation: 



2(u+2)-u=3(u-+)+9

We move all terms to the left:

2(u+2)-u-(3(u-+)+9)=0

We add all the numbers together, and all the variables

2(u+2)-u-(3(+u)+9)=0

We add all the numbers together, and all the variables

-1u+2(u+2)-(3(+u)+9)=0

We multiply parentheses

-1u+2u-(3(+u)+9)+4=0



We calculate terms in parentheses: -(3(+u)+9), so:

3(+u)+9

We multiply parentheses

3u+9

Back to the equation:

-(3u+9)



We add all the numbers together, and all the variables

u-(3u+9)+4=0

We get rid of parentheses

u-3u-9+4=0

We add all the numbers together, and all the variables

-2u-5=0

We move all terms containing u to the left, all other terms to the right

-2u=5

u=5/-2

u=-2+1/2

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