2x+3=(1/2)x+12

Solution for 2x+3=(1/2)x+12 equation:

2x+3=(1/2)x+12

We move all terms to the left:

2x+3-((1/2)x+12)=0


Domain of the equation: 2)x+12)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-((+1/2)x+12)+3=0

We multiply all the terms by the denominator


2x*2)x+12)-((+3*2)x+12)+1=0

We add all the numbers together, and all the variables

2x*2)x+12)-(6x+12)+1=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$