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(6x-1)(x+9)=0
We multiply parentheses ..
(+6x^2+54x-1x-9)=0
We get rid of parentheses
6x^2+54x-1x-9=0
We add all the numbers together, and all the variables
6x^2+53x-9=0
a = 6; b = 53; c = -9;
Δ = b2-4ac
Δ = 532-4·6·(-9)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-55}{2*6}=\frac{-108}{12} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+55}{2*6}=\frac{2}{12} =1/6 $
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