2x+3/x=7/4

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Solution for 2x+3/x=7/4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+3/x = 7/4 // - 7/4

2*x+3/x-(7/4) = 0

2*x+3/x-7/4 = 0

2*x^1+3*x^-1-7/4*x^0 = 0

(2*x^2-7/4*x^1+3*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-7/4*x^1+3*x^0) = 0

x^1

2*x^2+(-7/4)*x+3 = 0

2*x^2+(-7/4)*x+3 = 0

DELTA = (-7/4)^2-(2*3*4)

DELTA = -335/16

DELTA < 0

x in { } 

x belongs to the empty set

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