(Y-2)/3+(y+6)/4=16

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Solution for (Y-2)/3+(y+6)/4=16 equation: 


x in (-oo:+oo)

(Y-2)/3+(y+6)/4 = 16 // - 16

(Y-2)/3+(y+6)/4-16 = 0

(4*(Y-2))/(3*4)+(3*(y+6))/(3*4)+(-16*3*4)/(3*4) = 0

4*(Y-2)+3*(y+6)-16*3*4 = 0

4*Y+3*y-192+10 = 0

4*Y+3*y-182 = 0

(4*Y+3*y-182)/(3*4) = 0

(4*Y+3*y-182)/(3*4) = 0 // * 3*4

4*Y+3*y-182 = 0

x belongs to the empty set

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