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2x+3/2=2x+4/5-4x
We move all terms to the left:
2x+3/2-(2x+4/5-4x)=0
Domain of the equation: 5-4x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-4x)!=-5
x!=-5/1
x!=-5
x∈R
2x-(-2x+4/5)+3/2=0
We get rid of parentheses
2x+2x-4/5+3/2=0
We calculate fractions
There is no solution for this equation
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