4(2x+1)=x+32

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Solution for 4(2x+1)=x+32 equation: 



4(2x+1)=x+32

We move all terms to the left:

4(2x+1)-(x+32)=0

We multiply parentheses

8x-(x+32)+4=0

We get rid of parentheses

8x-x-32+4=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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