2x+3-8(x+1)=0

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Solution for 2x+3-8(x+1)=0 equation: 



2x+3-8(x+1)=0

We multiply parentheses

2x-8x-8+3=0

We add all the numbers together, and all the variables

-6x-5=0

We move all terms containing x to the left, all other terms to the right

-6x=5

x=5/-6

x=-5/6

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