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x2+12+31x=0
We add all the numbers together, and all the variables
x^2+31x+12=0
a = 1; b = 31; c = +12;
Δ = b2-4ac
Δ = 312-4·1·12
Δ = 913
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{913}}{2*1}=\frac{-31-\sqrt{913}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{913}}{2*1}=\frac{-31+\sqrt{913}}{2} $
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