2x+3+1/2x+65=180

Solution for 2x+3+1/2x+65=180 equation:

2x+3+1/2x+65=180

We move all terms to the left:

2x+3+1/2x+65-(180)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

2x+1/2x-112=0

We multiply all the terms by the denominator


2x*2x-112*2x+1=0

Wy multiply elements

4x^2-224x+1=0

a = 4; b = -224; c = +1;
Δ = b2-4ac
Δ = -2242-4·4·1
Δ = 50160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50160}=\sqrt{16*3135}=\sqrt{16}*\sqrt{3135}=4\sqrt{3135}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-224)-4\sqrt{3135}}{2*4}=\frac{224-4\sqrt{3135}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-224)+4\sqrt{3135}}{2*4}=\frac{224+4\sqrt{3135}}{8}
$