3(b+2)-(b-8)=3*b+8

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Solution for 3(b+2)-(b-8)=3*b+8 equation: 



3(b+2)-(b-8)=3b+8

We move all terms to the left:

3(b+2)-(b-8)-(3b+8)=0

We multiply parentheses

3b-(b-8)-(3b+8)+6=0

We get rid of parentheses

3b-b-3b+8-8+6=0

We add all the numbers together, and all the variables

-1b+6=0

We move all terms containing b to the left, all other terms to the right

-b=-6

b=-6/-1

b=+6

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