2x+3+(4x-1)/2=10

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Solution for 2x+3+(4x-1)/2=10 equation: 



2x+3+(4x-1)/2=10

We move all terms to the left:

2x+3+(4x-1)/2-(10)=0

We add all the numbers together, and all the variables

2x+(4x-1)/2-7=0

We multiply all the terms by the denominator


2x*2+(4x-1)-7*2=0

We add all the numbers together, and all the variables

2x*2+(4x-1)-14=0

Wy multiply elements

4x+(4x-1)-14=0

We get rid of parentheses

4x+4x-1-14=0

We add all the numbers together, and all the variables

8x-15=0

We move all terms containing x to the left, all other terms to the right

8x=15

x=15/8

x=1+7/8

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