2x+3(x-5)+1=2(2x+1)-3(x-1)

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Solution for 2x+3(x-5)+1=2(2x+1)-3(x-1) equation: 



2x+3(x-5)+1=2(2x+1)-3(x-1)

We move all terms to the left:

2x+3(x-5)+1-(2(2x+1)-3(x-1))=0

We multiply parentheses

2x+3x-(2(2x+1)-3(x-1))-15+1=0



We calculate terms in parentheses: -(2(2x+1)-3(x-1)), so:

2(2x+1)-3(x-1)

We multiply parentheses

4x-3x+2+3

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We add all the numbers together, and all the variables

5x-(x+5)-14=0

We get rid of parentheses

5x-x-5-14=0

We add all the numbers together, and all the variables

4x-19=0

We move all terms containing x to the left, all other terms to the right

4x=19

x=19/4

x=4+3/4

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