X-2-2(x+3)=3(3x-1)-4(2x-1)

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Solution for X-2-2(x+3)=3(3x-1)-4(2x-1) equation: 



X-2-2(X+3)=3(3X-1)-4(2X-1)

We move all terms to the left:

X-2-2(X+3)-(3(3X-1)-4(2X-1))=0

We multiply parentheses

X-2X-(3(3X-1)-4(2X-1))-6-2=0



We calculate terms in parentheses: -(3(3X-1)-4(2X-1)), so:

3(3X-1)-4(2X-1)

We multiply parentheses

9X-8X-3+4

We add all the numbers together, and all the variables

X+1

Back to the equation:

-(X+1)



We add all the numbers together, and all the variables

-1X-(X+1)-8=0

We get rid of parentheses

-1X-X-1-8=0

We add all the numbers together, and all the variables

-2X-9=0

We move all terms containing X to the left, all other terms to the right

-2X=9

X=9/-2

X=-4+1/2

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