2x+3(x-4)=-7(2x-3)+5

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Solution for 2x+3(x-4)=-7(2x-3)+5 equation: 



2x+3(x-4)=-7(2x-3)+5

We move all terms to the left:

2x+3(x-4)-(-7(2x-3)+5)=0

We multiply parentheses

2x+3x-(-7(2x-3)+5)-12=0



We calculate terms in parentheses: -(-7(2x-3)+5), so:

-7(2x-3)+5

We multiply parentheses

-14x+21+5

We add all the numbers together, and all the variables

-14x+26

Back to the equation:

-(-14x+26)



We add all the numbers together, and all the variables

5x-(-14x+26)-12=0

We get rid of parentheses

5x+14x-26-12=0

We add all the numbers together, and all the variables

19x-38=0

We move all terms containing x to the left, all other terms to the right

19x=38

x=38/19

x=2

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