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2(x+1)=3(x-6)
We move all terms to the left:
2(x+1)-(3(x-6))=0
We multiply parentheses
2x-(3(x-6))+2=0
We calculate terms in parentheses: -(3(x-6)), so:We get rid of parentheses
3(x-6)
We multiply parentheses
3x-18
Back to the equation:
-(3x-18)
2x-3x+18+2=0
We add all the numbers together, and all the variables
-1x+20=0
We move all terms containing x to the left, all other terms to the right
-x=-20
x=-20/-1
x=+20
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