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3(x+12)=7x-6+2x+7
We move all terms to the left:
3(x+12)-(7x-6+2x+7)=0
We add all the numbers together, and all the variables
3(x+12)-(9x+1)=0
We multiply parentheses
3x-(9x+1)+36=0
We get rid of parentheses
3x-9x-1+36=0
We add all the numbers together, and all the variables
-6x+35=0
We move all terms containing x to the left, all other terms to the right
-6x=-35
x=-35/-6
x=5+5/6
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